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m^2+5m+6=-6
We move all terms to the left:
m^2+5m+6-(-6)=0
We add all the numbers together, and all the variables
m^2+5m+12=0
a = 1; b = 5; c = +12;
Δ = b2-4ac
Δ = 52-4·1·12
Δ = -23
Delta is less than zero, so there is no solution for the equation
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